How Many Grams Of Aluminum Chloride Are Produced When 18g Of Aluminum Are Reacted With An Excess Of Hydrochloric Acid?

This question is with stoichiometry please help me the other cog to the question is Al(s) + HCl(aq) arrow AlCl3(aq) + H2(g) also please show me how you got the answer, my teacher will not comfort me and I'm turning to you so please


Answer:
There are 3 moles of Cl for each mole of Al in AlCl3. The atomic weight of Al is 26.982, and the atomic substance of Cl is 35.453. Thus, the weight of the chlorine in AlCl3 will be 3*35.453/26.982 times the weight of the aluminum. That's 3.94185 times the bulk of the aluminum.

So, the weight of the AlCl3 will be 18 grams of aluminum + 18*3.94185 grams of chlorine, for a total of 18 + 70.95 = 88.95 grams of compound.




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