How Many Oxygen Atoms Are In A 14.0g Sample Of Cu(NO3)2?
First we must calculate the gram molecular wt. Of Cu(NO3)2:
Add 14 + 16=30 X 2=60 then add Cu(64_g/1_mole)=124_g/1_mole of Cu(NO3)2
Our subsequent step is to calculate the no. Of atoms in Cu(NO3)2 based on Avogodro's number
6.023 x 1023 atoms/1_mole as follows:
14_g Cu(NO3)2 x 1/124_g/1_mole = 0.11_moles present x 6.023 X 1023= 6.8 x 1022 atoms present surrounded by the sample of Cu(NO3)2 (copper nitrate)
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Graphite has a crystal structure. It has two dimensional layers of carbon atoms chock-a-block one above the other. Each carbon in graphite is sp2 hybridized. Different layers of graphite are help together contained by the crystal by weak van der Waal's forces of attraction; the...