How Is 2x+2(x-5)=perimeter Of 70?
Answer:
You are apparently describing a rectangle whose perimeter is 70 units, and whose width is 5 unit less than its length.
The equation can be solved for the length...
2x + 2(x-5) = 70
2x + 2x - 10 = 70 (use the distributive property)
4x = 80 (add 10 to both sides, collect x terms)
x = 20 (divide both sides by 4)
x-5 = 15
A rectangle that is 20 units long and 15 unit wide will have a perimeter of 70 unit.
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