If 1500 Is Invested At A Rate Of 10% Compounded Monthly. What Is The Balance At The End Of 12 Years?
This is a word problem and I was not sure how to solve it. Please help.
Answer:
For this question, you will use the following formula
The harmonize at the end of the year = P (1 + r/n)^n*t
Where
Nominal interest rate per year= r = 10%
number of compounding per year = n = 12
Number of Years = t =12
P = investment = $1500
The balance at the end of the year = 1500 ( 1 + 10%/12)^12*12
The match at the end of 12 years = $4955.47
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Answer:
For this question, you will use the following formula
The harmonize at the end of the year = P (1 + r/n)^n*t
Where
Nominal interest rate per year= r = 10%
number of compounding per year = n = 12
Number of Years = t =12
P = investment = $1500
The balance at the end of the year = 1500 ( 1 + 10%/12)^12*12
The match at the end of 12 years = $4955.47
Resolved Questions:
When Is Science Can Be A Disadvantage?
If you're a catholic like me.. It's when you become cynical about God's existence.. But if you aren't when it leads to destruction and commotion..
What Are The Steps Of SEM?
I know these are fine but not what they are? The steps are as follows: Model specifications Elimination Elimination of fit Re specification of model Interpretation and communication Steps Of SEM
Which Is Larger 5/8 Or 7/8?
5/8 is just over half, and 7/8 is just almost full. With that said, 7/8 is the larger one. Or if you prefer, you can solve them. If you put it into a calculator, 5/8 = 0.625 and 7/8 = 0.875. The answer should be clear, it's still 7/8.