How Do You Solve Square Root Of X+20-x=0?
Answer:
Let y=√x, rewrite it as a quadratic equation, and solve in the usual way.
(√x) + 20 - x = 0
y + 20 - y2 = 0
y2 - y - 20 = 0
(y-5)(y+4) = 0
y = 5 or y = -4
From our definition of y, we know x = y2, so x = 25 or x = 16.
Check
(√25) + 20 - 25 = 0
5 + 20 - 25 = 0 (yes)
(√16) + 20 - 16 = 0
-4 + 20 - 16 = 0 (yes, note that we must choose the denial root to make this work)
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