3. Can You Determine An Equation For The Line Parallel To Y = 3x + 4 And Passing Through The Point (2, 1)? CONTINUED BELOW

4. Determine an equation for the line perpendicular to x – 3y – 1 = 0 and passing through the point (-3, -4).


Answer:
To find the equation of a parallel queue:

We have been given the equation y=3x+4 and we need to find a vein parallel to this and passing through the points(2,1).
Any two parallel lines have the same slope. So from the above equation we can see that m=3 since y=mx+c(y=3x+4) and m represents the slope of a rank.
Using this we can put these values in the slope intercept equation to find the parallel line:
We have x=2 and y=1
y-y1=m(x-x1)
y-1=(3)(x-2)
y-1=3x-6
y=3x-6+1
y=3x-5

To find the equation of a straight up line:

We have been given the equation x-3y-1=o and we obligation to find a line perpendicular to this and passing through the points(-3,-4).
To find the slope we will necessitate to convert this equation into a slope-intercept form(y=mx+c).
Therefore,
x-3y-1=0
x-1=3y
x(1/3) -1/3=y
so, y=x(1/3) -1/3

from this we can see that m=1/3
Any two perpendicular lines have slope that are inverse to each other and contrary in sign. So our perpendicular line will own slope equal to -3( inverse 1/3 ad change the sign to negative)
Using this we can put these values in the slope intercept equation to find the erect line:
We have x=-3 and y=-4
y-y1=m(x-x1)
y+4=(-3)(x+3)
y+4=-3x+9
y=-3x+9-4
y=-3x+5


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