If The Speed Of The Current Was 2 Mph, What Was The Speed Of The Boat?

A boat took 12 miles longer to travel 3 miles upstream than to travel the same distance downstream. A. 6 mph B. 8 mph C. 10 mph D. 11 mph E. 7 mph


Answer:
Let "b" = the speed of the boat, and "c" = the speed of the current.
3/(b-c) = 12/60 + 3/(b+c), assuming the difference in time is 12 minutes.

This equation can be expressed over a common denominator of b2-c2:
3(b+c)/(b2-c2) = (1/5)(b2-c2)/(b2-c2) + 3(b-c)/(b2-c2)
15b + 15c = b2-c2 + 15b - 15c    (multiply both sides by 5(b2-c2), expand the numerator)
b2 = c2 + 30c    (add c2+15c to both sides)
b = √(c(c+30)) = √(2(32)) = √64 = 8    (take square root, substitute numbers for the speed of the current)

The speed of the boat be 8 mph.




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