Can Anyone Solve X^2-3x-10=0?
Answer:
X2 - 3x - 10 = 0 is of the form ax2 + bx + c = 0, where a=1, b=-3, and c=-10, so we can use the quadratic formula to solve it.
x = (-b ±√(b2-4ac))/(2a) = (-(-3) ±√((-3)2 - 4(1)(-10)))/(2(1))
= (3 ±√(9 + 40))/2 = (3±√49)/2 = (3±7)/2
x = -2 or 5
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It can also be solved by factoring.
x2 - 3x - 10 = (x + 2)(x - 5) = 0
x+2 = 0
x = -2
x - 5 =0
x = 5
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