How Do I Solve This In Standard Form X^2 Y^2 9x-10y-5=0?
Answer:
It appears as though you want to solve
x2y2(9x) - 10y - 5 = 0
It can be rewritten to the standard form of a quadratic equation.
(9x3)y2 - 10y - 5 = 0
This can be solved for y using the quadratic formula.
y = (-(-10) ±√((-10)2 - 4(9x3)(-5)))/(2(9x3))
y = (10 ±√(100+180x3))/(18x3)
y = (5±√(25+45x3))/(9x3) (only defined for x>-.82207, and x≠0)
If you'd rather solve for x, you can do that this way.
9x3y2 = 5(2y-1) (add 10y+5 to both sides)
x3 = 5(2y-1)/(9y2) (divide both sides by 9y2)
x = (5(2y-1)/(9y2)) (take the cube root of both sides) (defined for y≠0)
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